Question

A mass of 3 kg is to rest vertically over a spring with a spring constant, k, of 1400 N/m. What is the energy absorbed by the spring?

Answer 1

$k=\frac{F}{m}$

$x=\frac{F}{k}$

$x=\frac{mg}{k}$

$mg=3\times 9.81=29.43N$

$x=\frac{29.43}{1400}$

$x=0.021m$

Energy stored

$$E=energy stored$$

$E=0.5k\times x^2$, $E=0.5\times 1400\times 0.021^2$ $E=0.30 joule$

$Energy stored$