Question #91701
A rocket of mass 14500kg accelerates at 210m/s2 for 32s from an initial speed of 5100m/s. (a) How fast will be rocket be travelling after the 32s?
(b) How much Kinetic Energy has the rocket gained?
1
Expert's answer
2019-07-19T14:38:19-0400

a)

v=v0+at==5100+210×32=11820msv=v_0+at=\\ = 5100+210\times 32= 11820 \frac{m}{s}

b)

Ekin=mv22ΔEkin=mv22mv022=14500×118202214500×510022=824TJE_{kin}=\frac{mv^2}{2}\\ \Delta E_{kin}=\frac{mv^2}{2}-\frac{mv_0^2}{2} = \\ \frac{14500\times 11820^2}{2}-\frac{14500\times 5100^2}{2} = 824 TJ


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