The work done by definition
"W=Fd\\cos\\theta"(a) The work done by the force of the tow truck on the car
"W=1500\\:\\rm{N}\\times 12\\:\\rm{m}\\times \\cos 0^{\\circ}=18\\: 000\\:\\rm{J}"(b) The work done by the frictional force
"W=810\\:\\rm{N}\\times 12\\:\\rm{m}\\times \\cos 180^{\\circ}=-9\\:720\\:\\rm{J}"
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