Answer to Question #86387 in Classical Mechanics for Merl

Question #86387
Light traveling in air is incident on a pane of glass (n = 1.6) at an angle of 25 degrees relative to the normal. What angle relative to the normal will it have once it is inside the glass?
1
Expert's answer
2019-03-19T12:08:34-0400
n=sin(i)sin(r)n = \frac{\sin(i)}{\sin(r)}1.6=sin(25)sin(r)1.6 = \frac{\sin(25)}{\sin(r)}r=sin1(sin(25)1.6)r=\sin^{-1}(\frac{\sin(25)}{1.6})

Thus, i = 15.3 degrees.


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