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Answer to Question #80770 in Classical Mechanics for Mayank
Question #80770
A car travels 1/4 of a circle of radius r .Ratio between distance to its displacement is
Expert's answer
The distance is
d=2πr/4=πr/2.
The displacements is
s=√2 r.
Ratio between distance to its displacement is
d/s=(πr/2)/(√2 r)=π/(2√2).
d=2πr/4=πr/2.
The displacements is
s=√2 r.
Ratio between distance to its displacement is
d/s=(πr/2)/(√2 r)=π/(2√2).
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