Question

Three masses arranged as shown on the right where 𝑚𝐴 = 2.00 [kg], 𝑚𝐵 = 1.00 [kg], and 𝑚𝐶 = 3.00 [kg]. What is the location of the center of mass? 

Answer 1

$x=\frac{m_ax_a+m_bx_b+m_cx_c}{m_a+m_b+m_c}=2.33,$

$y=\frac{m_ay_a+m_by_b+m_cy_c}{m_a+m_b+m_c}=3.00.$