how many turns of solenoid is required to produce a magnetic field having magnitude of 3.0 T upon the application of 600A current if the solenoid is 8.50 m long and is having 4500 turns. (note: \mu _(0)=4\pi x10^(-7)T. m/A).
"B=\\frac{\\mu_0 nI}l,\\implies"
"n=\\frac{Bl}{\\mu_0 I}=33820."
Comments
Leave a comment