Question

how many turns of solenoid is required to produce a magnetic field having magnitude of 3.0 T upon application of 600A current if the solenoid is 8.50 m long and is having 4500 turns. ( \mu _(0)=4\pi x10^(-7)T. m/A).

Answer 1

$B=\frac{\mu_0 nI}l,\implies$

$n=\frac{Bl}{\mu_0 I}=33820.$