Answer to Question #343183 in Classical Mechanics for elle

Question #343183

Barium ion with a 2+ charge travels at a speed 800 m/s and is acted upon by a magnetic force having a magnitude of 1700.0 N. Determine the magnitude of magnetic field acting perpendicularly on Ba^(2+).


1
Expert's answer
2022-05-20T13:19:46-0400
"F=qvB\\sin\\theta"

"B=\\frac{F}{qv\\sin\\theta}\\\\\n=\\frac{1700}{2*1.6*10^{-19}*800*\\sin90^\\circ}=6.64*10^{18}\\:\\rm T"


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