A ball mass of 0.2kg strikes on inclined surface and makes angle 60 degree and speed change from 30m/s to 20m/s what is the magnitude of impulse?
∆p=mv1+mv2cos60°=8 kg⋅ms.∆p=mv_1+mv_2\cos60°=8~\frac{kg\cdot m}s .∆p=mv1+mv2cos60°=8 skg⋅m.
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