A body of mass 3M at rest explodes into two pieces of mass M and 2M. What is the ratio of the kinetic energy of M to that of 2M? (Ans:2)
k=E2E1=2Mv22Mv22=2.k=\frac{E_2}{E_1}=\frac{\frac{2Mv^2}2}{\frac{Mv^2}2}=2.k=E1E2=2Mv222Mv2=2.
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