Question

An electric train develops a power of 1.0 MW when travelling at a constant speed of 50 ms-1. The net resistive force acting on the train is (Ans: 20 kN).

My work: P=FV, F=P/V, F=2x10^-6

Answer 1

$P=Fv,\implies$

$F=\frac Pv=\frac{10^6}{50}=20~kN.$