An electric train develops a power of 1.0 MW when travelling at a constant speed of 50 ms-1. The net resistive force acting on the train is (Ans: 20 kN).
My work: P=FV, F=P/V, F=2x10-6
"P=Fv,\\implies"
"F=\\frac Pv=\\frac{10^6}{50}=20~kN."
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