A constant force of 245 N is applied at a 48.2° angle to a mass of 62.1 kg as shown below. If the mass moves at a constant speed of 3.28 ms–1, determine its coefficient of dynamic friction.
Ans:0.206
N=mg+Fsin48.2°=792 N,N=mg+F\sin48.2°=792~N,N=mg+Fsin48.2°=792 N,
μ=Fcos48.2°N=0.2.\mu=\frac{F\cos 48 .2°}N=0 .2.μ=NFcos48.2°=0.2.
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