A rock is thrown from the top of a 36 m high cliff with an initial speed of 12 ms–1 at an angle of 52° to the horizon. How long will it take the rock to reach the bottom of the cliff?
t=2sg+vsinαg=14 s.t=\sqrt\frac{2s}g+\frac{v\sin\alpha}g=14~s.t=g2s+gvsinα=14 s.
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