Answer to Question #326027 in Classical Mechanics for Amrita

Question #326027

a body of mass 0.004kg executes SHM the force acting on the body when the displacement is 8cm is 0.024kgwt find the periodif the maximum velocity is 5m s find amplitude and maximum acceleration given g 9.8 m s²

1
Expert's answer
2022-04-11T12:07:26-0400

k=Fx=0.3 Nkg,k=\frac Fx=0.3~\frac N{kg},

ω=km=8.7 rads,\omega=\sqrt\frac km=8.7~\frac{rad}s,

T=2πω=0.73 s,T=\frac {2\pi}{\omega}=0.73~s,

A=vω=0.57 m,A=\frac v{\omega}=0.57~m,

a=ωv=43 ms2.a=\omega v=43~\frac m{s^2}.


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