a body of mass 0.004kg executes SHM the force acting on the body when the displacement is 8cm is 0.024kgwt find the periodif the maximum velocity is 5m s find amplitude and maximum acceleration given g 9.8 m s²
k=Fx=0.3 Nkg,k=\frac Fx=0.3~\frac N{kg},k=xF=0.3 kgN,
ω=km=8.7 rads,\omega=\sqrt\frac km=8.7~\frac{rad}s,ω=mk=8.7 srad,
T=2πω=0.73 s,T=\frac {2\pi}{\omega}=0.73~s,T=ω2π=0.73 s,
A=vω=0.57 m,A=\frac v{\omega}=0.57~m,A=ωv=0.57 m,
a=ωv=43 ms2.a=\omega v=43~\frac m{s^2}.a=ωv=43 s2m.
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