Answer to Question #323679 in Classical Mechanics for thembekalanga

Question

a particle falling under gravity is subject to a retarding force proportional to its velocity.find its position of time , if its starts from rest , and show that it will eventually reach a terminal velocity

Answer 1

Answer

Force is given by

F=kv

Equilibrium

Mg = kv

$K\frac{ds}{dt}=Mg\\$

By integration

$S=\frac{Mgt}{K}$

$S\alpha t$