A spring with mass of 2 kg has natural length of 0.5 m. A force of 25.6 N is required to maintain, it stretched to a length of 0.70 m. If the string is stretching to a length of 0.70 m and then released with initial velocity 0, find the position of mass at anytime t.
"k=\\frac Fl=51.2~\\frac Nm,"
"B=l'-l=0.2~m,"
"\\omega=\\sqrt{\\frac km}=5 .1~\\frac{rad}s,"
"x=0.5+0.2\\cos 5.1t."
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