A torque of 12 N m is applied to a solid, uniform puck of radius 0.50 m, causing the puck to accelerate at 5.7 rad/s2. What is the mass of the disk?
Answer
Torque
τ=Iα\tau=I\alphaτ=Iα
So mass
M=2τR2α=2∗120.5∗0.5∗5.7=16.84KgM=\frac{2\tau}{R^2\alpha}\\=\frac{2*12}{0.5*0.5*5.7}\\=16.84KgM=R2α2τ=0.5∗0.5∗5.72∗12=16.84Kg
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