Question

A stone is projected in a vertical plane from the ground with a velocity of 5 m/s. at an elevation of 60°. With what velocity, must another stone be projected at an angle of 45° in order to have the same horizontal range? Given g = 10 m/s^2

Answer 1

Answer

For same range of projectile , so velocity of second projectile

$v'=\frac{vcos\theta_1}{cos\theta_2}\\=\frac{5*cos60°}{cos45°}\\=3.54m/s$