A cube of mass 10 kg is at rest on a horizontal surface when it is subjected to a horizontal force P that varies with time t as P = 20t. If the static and kinetic coefficients of friction are both 0.4, calculate the velocity of the cube after 5 s.
v=∫0t(P−μmg)dt=(10t2−μmgt)∣0t=50 ms.v=\int_0^t(P-\mu mg)dt=(10t^2-\mu mgt)|_0^t=50~\frac ms.v=∫0t(P−μmg)dt=(10t2−μmgt)∣0t=50 sm.
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