solve for the electric flux that acts on a uniform electric field with a magnitude of 8000N/C approximately passes through a 10m^2 flat surface area
Answer
the electric flux is given by
ϕ=EAcosθ\phi=EA\cos\thetaϕ=EAcosθ
Putting all values
ϕ=800∗10∗cos0°=8000Wb.\phi=800*10*\cos0°\\=8000Wb.ϕ=800∗10∗cos0°=8000Wb.
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