Question #299347

solve for the electric flux that acts on a uniform electric field with a magnitude of 8000N/C approximately passes through a 10m^2 flat surface area


Expert's answer

Answer

the electric flux is given by

ϕ=EAcosθ\phi=EA\cos\theta

Putting all values

ϕ=80010cos0°=8000Wb.\phi=800*10*\cos0°\\=8000Wb.






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