Question #299244

A body of 4kg mass travelling at 8m/s² collides with a stationary body of mass 12kg, both being constrainted in their motion by the same frictionless guides. Find their velocities and loss of kinetic energy, if coefficient of restitution is 1 and (b) if it is 0.5

1
Expert's answer
2022-02-18T08:22:14-0500

Given:

v1=8m/sv_1=8\:\rm m/s

m1=4.0kgm_1=4.0\:\rm kg

v2=0v_2=0

m2=12kgm_2=12\:\rm kg


(a) e=1e=1

v1v2=v1v2=8|v_1'-v_2'|=|v_1-v_2|=8

Hence


m1v1=m1v1+m2(8v1)m_1v_1=m_1v_1'+m_2(8-v_1')

48=4v1+12(8v1)4*8=4v_1'+12(8-v_1')

v1=8m/sv_1'=8\:\rm m/s

v2=0v_2'=0

The loss of kinetic energy is zero.

(b) e=0.5e=0.5

v1v2=0.5v1v2=4|v_1'-v_2'|=0.5|v_1-v_2|=4

Hence


m1v1=m1v1+m2(v10.5v1)m_1v_1=m_1v_1'+m_2(v_1'-0.5v_1)

48=4v1+12(v14)4*8=4v_1'+12(v_1'-4)

v1=5m/sv_1'=5\:\rm m/s

v2=1m/sv_2'=1\:\rm m/s

The loss of kinetic energy

ΔE=482/2(452/2+1212/2)\Delta E=4*8^2/2-(4*5^2/2+12*1^2/2)

ΔE=72J\Delta E=72\:\rm J


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