Question #286490

What is the angular displacement of a 0.7m diameter wheel that rolls 3m clockwise?

1
Expert's answer
2022-01-11T11:01:03-0500

The arc traveled is given by

S=θ  rS=\theta\;r

Where.

S=3  mS=3\;m is the linear offset or arc traveled.

rr Is the radius.

θ\theta Is the angular displacement.


The diameter is d=0.7  md=0.7\;m


The radius is half the diameter that is to say.

r=d2r=0.7  m2r=0.35  mr=\dfrac{d}{2}\\ r=\dfrac{0.7\;m}{2}\\ r=0.35\;m


Obtaining the expression for the angular displacement.

S=θ  rθ  r=Sθ=SrS=\theta\;r\\ \theta\;r=S\\ \theta=\dfrac{S}{r}\\

Evaluating numerically.

θ=Srθ=3.0  m0.35  mθ=8.6  rad\theta=\dfrac{S}{r}\\ \theta=\dfrac{3.0\;m}{0.35\;m}\\ \theta=8.6\;rad


The angular displacement is θ=8.6  rad\theta=8.6\;rad


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