Answer to Question #286180 in Classical Mechanics for dummy

Question

Stacy confirms that Marcus dropped the ball with a mass of 1.20 [kg]. The ball hits the floor at 2.40 [m/s] and bounces back at 2.00 [m/s]. The time of contact between the ball and the floor is 0.1 [s]. Assuming an elastic collision and the upward direction being the positive direction, what is the average force that the floor exerts on the ball during the impact?

Answer 1

$$F_{avg}\Delta t=m\Delta v,$$ $$F_{avg}=\dfrac{m\Delta v}{\Delta t}=\dfrac{m(v_f-v_i)}{\Delta t},$$ $$F_{avg}=\dfrac{1.2\ kg\times(2\ \dfrac{m}{s}-(-2.4\ \dfrac{m}{s}))}{0.1\ s}=52.8\ N.$$