Question #285938

A=yz then it's gradient is






1
Expert's answer
2022-01-10T09:17:00-0500

The gradient of a scalar field is given by

gradA=i^Ax+j^Ay+k^Az{\rm grad} A=\hat i \frac{\partial A}{\partial x}+\hat j \frac{\partial A}{\partial y}+\hat k \frac{\partial A}{\partial z}

In our case

gradA=i^(yz)x+j^(yz)y+k^(yz)z{\rm grad} A=\hat i \frac{\partial (yz)}{\partial x}+\hat j \frac{\partial (yz)}{\partial y}+\hat k \frac{\partial (yz)}{\partial z}

gradA=j^z+k^y{\rm grad} A=\hat j z+\hat k y


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