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Answer to Question #285487 in Classical Mechanics for steph
Question #285487
a 60kg man on a 3kg stretcher that is 2.6m long. his center of mass is 1m from one end. how much force must be entered to keep horizontal
Expert's answer
"Fl=mg\\frac l2+Mgh,"
"F=\\frac gl(m\\frac l2+Mh)=241~N."
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