A = -2î +6ĵ & B = 2î - 3j
A→=−2i^+6j^\overrightarrow{A}=-2\hat{i}+6\hat{j}A=−2i^+6j^
B→=2i^−3j^\overrightarrow{B}=2\hat{i}-3\hat{j}B=2i^−3j^
Dot product of both vector
A→.B→=−22\overrightarrow{A}.\overrightarrow{B}=-22A.B=−22
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