Answer to Question #279825 in Classical Mechanics for dilon

Question

A = -2î +6ĵ & B = 2î - 3j

Answer 1

$\overrightarrow{A}=-2\hat{i}+6\hat{j}$

$\overrightarrow{B}=2\hat{i}-3\hat{j}$

Dot product of both vector

$$\overrightarrow{A}.\overrightarrow{B}=(-2\hat{i}+6\hat{j}).(2\hat{i}-3\hat{j})=-4-18=-22$$

$\overrightarrow{A}.\overrightarrow{B}=-22$