Answer to Question #279825 in Classical Mechanics for dilon

Question #279825

A = -2î +6ĵ & B = 2î - 3j


1
Expert's answer
2021-12-15T22:33:53-0500

A=2i^+6j^\overrightarrow{A}=-2\hat{i}+6\hat{j}

B=2i^3j^\overrightarrow{B}=2\hat{i}-3\hat{j}

Dot product of both vector


A.B=(2i^+6j^).(2i^3j^)=418=22\overrightarrow{A}.\overrightarrow{B}=(-2\hat{i}+6\hat{j}).(2\hat{i}-3\hat{j})=-4-18=-22

A.B=22\overrightarrow{A}.\overrightarrow{B}=-22


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