Question #276328

A wave with a frequency of 300 per second travels from water in which its velocity is 1450 m/s to air which its velocity is 331.5 m/s. Calculate the wavelengths in each medium


1
Expert's answer
2021-12-08T10:03:00-0500

λ=vf\lambda= \frac{v}{f}

λwatter=14503004,83m\lambda_{watter}= \frac{1450}{300}\approx4,83m


λair=331.53001.11m\lambda_{air}= \frac{331.5}{300}\approx 1.11m


Answer: λwatter=4.83m;λair=1.11m\text{Answer: }\lambda_{watter}= 4.83m; \lambda_{air}= 1.11m


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