A wave with a frequency of 300 per second travels from water in which its velocity is 1450 m/s to air which its velocity is 331.5 m/s. Calculate the wavelengths in each medium
λ=vf\lambda= \frac{v}{f}λ=fv
λwatter=1450300≈4,83m\lambda_{watter}= \frac{1450}{300}\approx4,83mλwatter=3001450≈4,83m
λair=331.5300≈1.11m\lambda_{air}= \frac{331.5}{300}\approx 1.11mλair=300331.5≈1.11m
Answer: λwatter=4.83m;λair=1.11m\text{Answer: }\lambda_{watter}= 4.83m; \lambda_{air}= 1.11mAnswer: λwatter=4.83m;λair=1.11m
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