Answer to Question #276328 in Classical Mechanics for gelo

Question

A wave with a frequency of 300 per second travels from water in which its velocity is 1450 m/s to air which its velocity is 331.5 m/s. Calculate the wavelengths in each medium

Answer 1

$\lambda= \frac{v}{f}$

$\lambda_{watter}= \frac{1450}{300}\approx4,83m$

$\lambda_{air}= \frac{331.5}{300}\approx 1.11m$

$\text{Answer: }\lambda_{watter}= 4.83m; \lambda_{air}= 1.11m$