An earth satellite has a speed of 28070 km/hr when it is at its perigee of 220 km above Earth's surface. Find the apogee distance its speed at apogee, and its period of revolution.
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Expert's answer
2021-12-03T12:44:29-0500
From the speed at the perigee, find the semi-major axis of the satellite's orbit:
vper=GM(r2per−a1),a=2GM−vper2rperGMrper=2GM−vper2(RE+hper)GM(RE+hper)=6636 km.
Find the apogee distance:
rap=2a−rper=6677 km.
From the apogee distance, find the speed at the apogee:
vap=GM(r2ap−a1)=7.7 km.
Apply Kepler's third law to find the period of revolution:
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