1.m=770kg
T1=20°CT2=80°Cg=9.8s2mfrom
ρ1=1.204m3kg
ρ2=0.9994m3kg
Fa=ρ1gV
let m1 air mass in a balloon
Fa−mg−m1g≥0
m1=ρ2V
ρ1gV−mg−ρ2gV≥0
V≥ρ1−ρ2m=1.204−0.9994770≈3763m3
Answer: V≥3763m3
2.
ρw=1000m3kg
ρb=800m3kg
ab=600mm=0.6m
ac=1.2m
hc=1m
Vc=ac2h=1.44m3
Vb=ab3=0.216m3
mb=ρbVb=172.8kg
let V1 volume of the block immersed in water
Fa=ρwgV1
Fa−mbg=0
ρwgV1−mbg=0
V1=ρwmb=0.1728m3
h1=ac2Vc+V1=1.12m
Answer: 1.12m
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