Question #271796

An apple is falling down from a height of 20m and then hit a

person. Assume that the mass of the apple is 200g. The

duration of impact is 0.001 sec and that the area of the

bone is 1 cm2. (a) Calculate the impulsive force applied to

the person. (b) If the rupture strength for body tissue is

about 5 X 106 dyn/cm2 will the impact force lead to serious

injury for the person?


1
Expert's answer
2021-11-26T10:29:03-0500

h=20mm=200g=0.2kgΔt=0.001sS=1cm2pmax=5106dyncm2=50Ncm2h = 20m\newline m =200g =0.2kg\newline \Delta t = 0.001s\newline S =1cm^2\newline p_{max}= 5*10^6\frac{dyn}{cm^2}=50\frac{N}{cm^2}

g=9.8ms2g = 9.8\frac{m}{s^2}

Apple speed at the end of the fall:\text{Apple speed at the end of the fall:}

v=2gh=29.82019.8msv =\sqrt{2gh}=\sqrt{2*9.8*20}\approx19.8\frac{m}{s}

Apple’s impulse at the end of the fall:\text{Apple's impulse at the end of the fall:}

J=mv=0.219.8=3.96 kgmsJ = mv =0.2*19.8=3.96\ kg\frac{m}{s}

The force of the apple on the body:\text{The force of the apple on the body:}

J=FΔtJ= F\Delta t

F=JΔt=3.960.001=3960NF = \frac{J}{\Delta t}= \frac{3.96}{0.001}=3960N

The pressure of the apple on the body during the impact:\text{The pressure of the apple on the body during the impact:}

p=FS=39601=3960Ncm2p = \frac{F}{S}=\frac{3960}{1}=3960\frac{N}{cm^2}

p>pmax hence p>p_{max}\text{ hence }

impact force will cause human trauma\text{impact force will cause human trauma}


Answer:\text{Answer:}

a)F=3960Na)F =3960N

b)impact force will cause human traumab)\text{impact force will cause human trauma}



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