Question

Isaac applies a force of 40N at an angle of 60°up from the horizontal to a wooden rod using a spring scale.If he generatesa torque of 73 m.N,how long was the rod?

Answer 1

$F = 40N$

$\alpha = 60\degree$

$\tau=73N*m$

$\tau = F*r$

$\tau=|r|*|F|*\sin \alpha$

$r= \frac{\tau}{F*\sin \alpha}=\frac{73}{40*\sin 60\degree}\approx2.11m$

$\text{Answer:}2.11m$