Question #267551

The bob of the pendulum is 200 g. It is swinging at a height of 1 m. The length of the pendulum is 1 m. Find the values of GPE, KE, and total mechanical energy at a height of 1 m, 0.5 m and 0.25 m and at its lowest point.



1
Expert's answer
2021-11-17T10:37:19-0500

m=200g=0.2kgm = 200g = 0.2kg

g=9.8ms2g = 9.8\frac{m}{s^2}

E=GPE+KEE = GPE +KE

GPE=mghGPE = mgh


for h=1m\text{for }h=1m

KE=0KE = 0

GPE=0.29.81=1.96JGPE = 0.2*9.8*1= 1.96J

E=1.96JE = 1.96J


for h=0.5mE=1.96JGPE=0.29.80.5=0.98JKE=EGPE=1.960.98=0.98J\text{for }h=0.5m\newline E = 1.96J\newline GPE = 0.2*9.8*0.5=0.98J\newline KE = E-GPE = 1.96-0.98 =0.98J


for h=0.25mE=1.96JGPE=0.29.80.25=0.49JKE=EGPE=1.960.49=1.47J\text{for }h=0.25m\newline E = 1.96J\newline GPE = 0.2*9.8*0.25=0.49J\newline KE = E-GPE = 1.96-0.49 =1.47J


for h=0mE=1.96JGPE=0KE=EGPE=1.96J\text{for }h=0m\newline E = 1.96J\newline GPE = 0\newline KE = E-GPE = 1.96J



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