Question #266925

Two blocks, with masses 4.00 kg and 8.00 kg are connected by a string and slide down a

30 inclined plane (see figure). The coefficient of kinetic friction between the 4.00 kg block and the

plane is 0.25; that between the 8.00 kg block and the plane is 0.35. Calculate

a) the acceleration of each block

b) the tension in the string


Expert's answer

Determine the acceleration. Begin with writing equations for both blocks using Newton's second law:

4:T+mgsinθμ4mgcosθ=ma,8:T+Mgsinθμ8Mgcosθ=Ma.4:-T+mg\sin\theta-\mu_4mg\cos\theta=ma,\\ 8:T+Mg\sin\theta-\mu_8Mg\cos\theta=Ma.


The solution of this system is


a=g(m+M)sinθ(μ4m+μ8M)cosθm+M=2.21 m/s2. T=M(a+g(μ8cosθsinθ))=2.24 N.a=g\frac{(m+M)\sin\theta-(\mu_4m+\mu_8M)\cos\theta}{m+M}=2.21\text{ m/s}^2.\\\space\\ T=M(a+g(\mu_8\cos\theta-\sin\theta))=2.24\text{ N}.


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