Question

A 400kg mass on a 30 degree inclined plane is acted upon by a force equal to 4800N at an angle 30 degree with the incline as shown in the figure below.

Answer 1

a)

$m\vec a=\vec F+m\vec g,$

$a=\frac Fm\cos 30°-g\sin 30°=5.5~\frac m{s^2},$

b)

$m\vec a=\vec F+m\vec g+\vec F_{fr},$

$a=\frac Fm\cos 30°-g\sin 30°-\mu g\cos 30°=3.8~\frac m{s^2}.$