Betty walks 2km due west then 2km due south calculate the displacement
sw=2kms_w= 2kmsw=2km
ss=2kms_s= 2kmss=2km
W⃗⊥S⃗\vec{W}\perp \vec SW⊥S
s=sw2+ss2=22+22≈2.83kms= \sqrt{s_w^2+s_s^2}=\sqrt{2^2+2^2}\approx2.83kms=sw2+ss2=22+22≈2.83km
Answer: 2.83km\text{Answer: }2.83kmAnswer: 2.83km
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