Question #257670
In a loading van the driver pushed a 15kg crate for 5 meters up the ramp. She had to push with a force of 132N and the vertical height gained was 1.3m. What was the efficiency of pushing this crate up the ramp onto the back of the van?
1
Expert's answer
2021-10-28T08:52:19-0400

F=132NF = 132N

s=5ms = 5m

m=15kgm= 15kg

h=1.3mh= 1.3m

g=9.8ms2g=9.8\frac{m}{s^2}

η=WoutputWinput100%\eta= \frac{W_{output}}{W_{input}}*100 \%

Woutput=mgh=159.81.3=191.1JW_{output }= mgh = 15*9.8*1.3= 191.1J

Winput=Fs=1325=660JW_{input}=Fs=132*5=660J

η=191.1660100%29%\eta= \frac{191.1}{660}*100\%\approx 29\%


Answer: η=29%\text{Answer: }\eta = 29\%


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