Question

Shaurya is going tobogganing.  Shaurya and the toboggan have a combined mass of 95 kg.  Once Shaurya reaches the bottom of the hill, he is travelling at 6.5 m/s.  After travelling for 14.6 m over level ground, he comes to a stop.  What is the coefficient of kinetic friction between Shaurya’s toboggan and the snow

Answer 1

Apply work-energy theorem:

$$\mu mgx=\frac12mv^2,\\\space\\ \mu=\frac{v^2}{gx}=0.3.$$