Pair=6.2N
Pwater=4.5N
Punliquid=5.3N
g=9.8s2m
in water:
ρwater=1000m3kg
BFwater=Pair−Pwater=6.2−4.5=1.7N
BFwater=ρwatergVstone
Vstone=ρwatergBFwater=1000∗9.81.7≈1.73∗10−4m3
in air :
Pair=mstoneg
ρstone=Vstonemstone=gVstonePair
ρstone=9.8∗1.73∗10−46.2=3.66∗103m3kg
in an unknown liquid:
BFunliquid=Pair−Punliquid=6.2−5.3=0.9N
BFunliquid=ρunliquidgVstone
ρunliquid=gVstoneBFunliquid=9.8∗1.73∗10−40.9=0.53∗103m3kg
Answer:
a)ρstone=3.66∗103m3kg
ρunliquid=0.53∗103m3kg
b)BFunliquid=0.9N
c)BFwater=1.7N
d)Vstone=1.73∗10−4m3
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