Question #253509
a photon of yellow light of frequency
5.0 * 10^14Hz is emitted in a time of
10^-8 seconds
evaluate 1. the length of the wave train
2. the number of complete oscillations present in the wave train
1
Expert's answer
2021-10-20T10:39:02-0400

1) We can find the length of the wave train as follows:


l=cΔt=3×108 ms×108 s=3.0 m.l=c\Delta t=3\times10^8\ \dfrac{m}{s}\times10^{-8}\ s=3.0\ m.

2) Let's first find the length of the wave:


λ=cf=3×108 ms5.0×1014 Hz=6.0×107 m.\lambda=\dfrac{c}{f}=\dfrac{3\times10^8\ \dfrac{m}{s}}{5.0\times10^{14}\ Hz}=6.0\times10^{-7}\ m.


We can find the number of complete oscillations present in the wave train as follows:


N=lλ=3.0 m6.0×107 m=5.0×106.N=\dfrac{l}{\lambda}=\dfrac{3.0\ m}{6.0\times10^{-7}\ m}=5.0\times10^6.

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