Question #253509

a photon of yellow light of frequency
5.0 * 10^14Hz is emitted in a time of
10^-8 seconds
evaluate 1. the length of the wave train
2. the number of complete oscillations present in the wave train

Expert's answer

1) We can find the length of the wave train as follows:


l=cΔt=3×108 ms×108 s=3.0 m.l=c\Delta t=3\times10^8\ \dfrac{m}{s}\times10^{-8}\ s=3.0\ m.

2) Let's first find the length of the wave:


λ=cf=3×108 ms5.0×1014 Hz=6.0×107 m.\lambda=\dfrac{c}{f}=\dfrac{3\times10^8\ \dfrac{m}{s}}{5.0\times10^{14}\ Hz}=6.0\times10^{-7}\ m.


We can find the number of complete oscillations present in the wave train as follows:


N=lλ=3.0 m6.0×107 m=5.0×106.N=\dfrac{l}{\lambda}=\dfrac{3.0\ m}{6.0\times10^{-7}\ m}=5.0\times10^6.

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