Answer to Question #247924 in Classical Mechanics for Alex

Question #247924

A dog chases a cat across the 15m yard before the cat climbs a 4m tree. What is the finalndisplacement lf the cat?


1
Expert's answer
2021-10-07T08:50:23-0400

Let point O be the initial position of the catpoint H is the beginning of a tree trunk located at ground levelpoint A the position of the cat on the tree\text{Let point O be the initial position of the cat}\newline \text{point H is the beginning of a tree trunk located at ground level}\newline \text{point A the position of the cat on the tree}

OH=15;AH=4;(OA,HA)=90°|\vec {OH}|=15;|\vec {AH}|=4;\angle(\vec {OA},\vec {HA})=90\degree

S=OAS = |\vec {OA}|

OA=OH+AH\vec {OA} = \vec {OH}+ \vec {AH}

OA=OH2+AH2=152+4215.52m| \vec {OA} |= \sqrt{|\vec {OH}|^2+ |\vec {AH}|^2}= \sqrt{15^2+ 4^2}\approx15.52m


Answer: 15.52m\text{Answer: }15.52m


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