Question #247924

A dog chases a cat across the 15m yard before the cat climbs a 4m tree. What is the finalndisplacement lf the cat?


Expert's answer

Let point O be the initial position of the catpoint H is the beginning of a tree trunk located at ground levelpoint A the position of the cat on the tree\text{Let point O be the initial position of the cat}\newline \text{point H is the beginning of a tree trunk located at ground level}\newline \text{point A the position of the cat on the tree}

∣OH⃗∣=15;∣AH⃗∣=4;∠(OA⃗,HA⃗)=90°|\vec {OH}|=15;|\vec {AH}|=4;\angle(\vec {OA},\vec {HA})=90\degree

S=∣OA⃗∣S = |\vec {OA}|

OA⃗=OH⃗+AH⃗\vec {OA} = \vec {OH}+ \vec {AH}

∣OA⃗∣=∣OH⃗∣2+∣AH⃗∣2=152+42≈15.52m| \vec {OA} |= \sqrt{|\vec {OH}|^2+ |\vec {AH}|^2}= \sqrt{15^2+ 4^2}\approx15.52m


Answer: 15.52m\text{Answer: }15.52m


LATEST TUTORIALS
APPROVED BY CLIENTS