The volume of a sphere is to be computed from the measured value of its radius. Estimate the maximum permissible percentage error in the measurement if the percentage error in the volume must be kept within ±6%.
V=43πR3V =\frac{4}{3}\pi R^3V=34πR3
ϵ(V)=ϵ(43)+ϵ(π)+3∗ϵ(R)\epsilon(V)= \epsilon(\frac{4}{3})+\epsilon(\pi)+3*\epsilon(R)ϵ(V)=ϵ(34)+ϵ(π)+3∗ϵ(R)
∣ϵ(V)∣<6%|\epsilon(V)|<6\%∣ϵ(V)∣<6%
∣ϵ(43)+ϵ(π)+3∗ϵ(R)∣<6%|\epsilon(\frac{4}{3})+\epsilon(\pi)+3*\epsilon(R)|<6\%∣ϵ(34)+ϵ(π)+3∗ϵ(R)∣<6%
∣3∗ϵ(R)∣<6%|3*\epsilon(R)|<6\%∣3∗ϵ(R)∣<6%
ϵ(R)±2%\epsilon(R) ±2\%ϵ(R)±2%
Answer: maximum permissible error in measuring the radius of the ball±2%\text{Answer: maximum permissible error in measuring }\newline \text{ the radius of the ball} ±2\%Answer: maximum permissible error in measuring the radius of the ball±2%
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