a=15cm=0.15m
ρw=1∗103m3kg
ρc=655m3kg
g=9.8m3kg
Forces acting on a wooden cube:
FA=ρwgV1
V1−The volume of a part of the cube immersed in
water and also the volume of displaced water
Fg=mcg
mc−mass of a wooden cube
mc=Vcρc=a3ρc
Fg=FA
a3ρcg=ρwgV1
V1=ρwga3ρc=1030.153∗665=2.24∗10−3m3
m1−mass of displaced water
m1=ρwV1=2.24kg
Answer:
2.24kg−mass of displaced water
2.24∗10−3m3-volume of displaced water
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