Question

An x-ray photon of initial frequency 3.0x10^-19 sec^-1 collides with an electron and is scattered through 60

Answer 1

$$\lambda'-\lambda=\frac{h}{mc}(1-\cos{\theta})\\ \frac{1}{f'}-\frac{1}{f}=\frac{h}{mc^2}(1-\cos{\theta}) \\ \frac{1}{f'}-\frac{1}{3\cdot10^{-19}}=\frac{6.63\cdot10^{-34}}{(9.1\cdot10^{-31})(3\cdot10^{8})^2}(1-\cos{60})\\f'=3\cdot10^{-19}\ Hz$$