Answer to Question #229398 in Classical Mechanics for Haroun

Question #229398
A small ball rolls horizontally off the edge of a tabletop that is 1,2 m high. It strikes the floor at a point 1,52 m horizontally away from the edge of the table.

1. How long is the ball in the air?
2. What is the speed at the instant it leaves the table?
1
Expert's answer
2021-08-25T12:25:33-0400

1)

t=2hg=0.5 s,t=\sqrt{\frac{2h}g}=0.5~s,

2)

vy=2gh=4.85 ms,v_y=\sqrt{2gh}=4.85~\frac ms,

vx=l/t=3.04 ms,v_x=l/t=3.04~\frac ms,

v=vx2+vy2=5.72 ms.v=\sqrt{v_x^2+v_y^2}=5.72~\frac ms.


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Comments

Assignment Expert
26.08.21, 18:51

Dear Haroun, you are right. Thank you for comment


Haroun
25.08.21, 20:39

By answer 2) isn't the Vx, supposed to be displacement(l) divided by the time (t)? Because isn't velocity the quotient of displacement & time?

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