Answer to Question #226088 in Classical Mechanics for Cpha

Question #226088

A 5.0-{\rm kg} block is suspended from the ceiling by a strong spring and released to perform simple harmonic motion with a period of 0.65 {\rm \;s} . The block is brought to rest, and the length of the spring with the block attached is measured. By how much is this length reduced when the block is removed?


1
Expert's answer
2021-08-16T08:39:07-0400

The period of a spring pendulum is


T=2πmk, k=4π2mT2=467.2 N/m.T=2\pi\sqrt{\frac mk},\\\space\\ k=\frac{4\pi^2m}{T^2}=467.2\text{ N/m}.

According to equilibrium of forces:


mg=kx, x=mgk=0.1049 m.mg=kx,\\\space\\x=\frac{mg}{k}=0.1049\text{ m}.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment