body of mass 0.25 KG moving with velocity 12 m/s is stopped by applying a force of 0.6 N calculate the time taken to stop the body. Also calculate the impulse of this force.
p=mv=3 kg⋅ms,p=mv=3~\frac {kg\cdot m}s,p=mv=3 skg⋅m,
F=pt, ⟹ t=pF=5 s.F=\frac pt,\implies t=\frac pF=5~s.F=tp,⟹t=Fp=5 s.
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