Answer to Question #222225 in Classical Mechanics for mazon47

Question #222225

A locomotive with a mass of 3E5 is accelerating at 0.4m/s2 up an incline of 1 in 20. The rolling resistance is 20 kN of the locomotive. At the instant when the speed of the locomotive is 63 km/h, calculate:

6.1. The power required. (10)

6.2. The kinetic energy of the locomotive. (8)


1
Expert's answer
2021-08-04T04:40:26-0400

m=3105kgm = 3*10^5kg

a=0.4ms2a = 0.4\frac{m}{s^2}

Frol=20000NF_{rol} = 20000N

v=63kmh=17.5msv=63\frac{km}{h }=17.5\frac{m}{s}

P=FlocvP = F_{loc}v

F=maF = ma

F=FlocFrolmgsinαF = F_{loc}-F_{rol}-mg\sin\alpha

sinα=120=0.05\sin \alpha= \frac{1}{20}=0.05

Floc=ma+Frol+mgsinα=287000NF_{loc}=ma+F_{rol}+mg\sin\alpha=287000N

6.1

P=Flocv=5022500WP = F_{loc}v= 5022500W

6.2

Ek=mv22=45937500JE_k = \frac{mv^2}{2}=45937500J


Answer:\text {Answer}:

6.1 P = 5022500W

6.2 Ek = 45937500J


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