1)
Δh=3.2m
m=60kg
g=9.8s2m
W=mgΔh=60∗9.8∗3.2=1.88∗103J
m1=10kg
v0=0;v1=11sm
t=5s
2)
a=tv1−v0=511−0=2.2s2m
3)
F=ma=10∗2.2=22N
4)
s=v0t+2at2=0+22.2∗25=27.5m
5)
W1=Fs=22∗27.5=605J
Answer:
1)...the work done against gravity is 1.88∗103J
2) The acceleration of the object is 2.2m/s2
3) The horizontal force given to the object is 22N
4) The distance travelled by the object is 27.5m
5) The work done on the object is 605J
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