A stone of mass 1kg is thrown vertically downward from a rope at a velocity of 2m/s. At the moment it hits the soils, the stone has a kinetic energy of 200J. What is the height from which the stone is thrown?
E=mv22+mgh,E=\frac{mv^2}2+mgh,E=2mv2+mgh,
h=Emg−v22g=19.8 m.h=\frac E{mg}-\frac{v^2}{2g}=19.8~m.h=mgE−2gv2=19.8 m.
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